Answers: 2
![Ka=\frac{[H^+][ClO_4^-]}{HClO_4} =3.00x10^{-8}](/tpl/images/0711/3092/4bf0c.png)
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![pH=-log([H^+])=-log(2.45x10^{-5})\\\\pH=4.6](/tpl/images/0711/3092/32e4d.png)
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The Ka of hypochlorous acid (HClO) is 3.00 x 10-8. What is the pH at 25 ∘C of an aqueous solution th...
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