Consider the following intermediate chemical equations. 2
C(s)+102(g) → CO(g)
CO(g) + 2O2(g) –> C0,00)
How will oxygen appear in the final chemical equation?
O O2(g)
as a product
O2(g)
as a reactant
O(g) as a product
20 (9) as a reactant

O O2(g) as a product

Explanation:

it is because oxygen is a gas and it must be given off in form of combustion

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."

lol idk man i guess u gotta ask bill nye the science guy