A saturated solution of NaCl is formed by adding 500.g of NaCl to 0.500L of water. The excess solid NaCl is filtered from the solution, and after being dried in an oven, the mass was determined to be 346.8g. Required:
What is the solubility of NaCl?

4.96 mol/dm³

Explanation:

From the question,

Mass of NaCl that dissolved in 0.5L of water = 500-346.8 = 153.2 g.

Therefore, 145.2(1/0.5)g of NaCl will dissolve in 1 L of water

mass of NaCl that will dissolve in 1 L of water = 290.4 g/dm³

Molar mass of NaCl = 58.5 g/mol.

Solubility is the amount of substance in mol that will dissolve in 1 L or 1 dm³ Solution.

 solubility in (mol/dm³) = solubility in (g/dm³)/molar mass.

solubility in (mol/dm³) = 290.4/58.5

solubility in (mol/dm³) = 4.96 mol/dm³

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o