A 3.0 mole sample of KCIO3 was decomposed according to the equation: 2KCIO3(s) ===> 2KCI(s) + 3O2(g)
How many moles of oxygen (O2) will be formed?
o 2.5 moles
4.0 moles
3.0 moles
2.0 moles
4.5 moles

4.5 moles

Explanation:

From the equation, the mole ratio of KClO3: O2 = 2: 3

Which means, every 2 moles of KClO3 forms 3 moles of O2.

Let the no. of moles of O2 formed be y.

2y = 3x3

2y = 9

y = 4.5 moles

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol

answer: i dont know the answer but this might

explanation:

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