The mass percentage of hydrochloric acid within a solution is 22.00%. Given that the density of this solution is 1.110 g/mL, find the molarity of the solution.

The molarity of the solution is 6.67 M.

From the question given above, the following data were obtained:

Mass percent of HCl = 22%

Density of solution = 1.110 g/mL

Molarity of solution =? Next, we shall determine the mass of HCl in the solution.

Percentage by mass of HCl = 22%

Mass of HCl =?

Mass of HCl =

Mass of HCl = 0.22

NOTE: Assume the mass of the solution to be 1 g.

Next, we shall determine the number of mole in 0.22 g of HCl. This can be obtained as follow:

Molar mass of HCl = 1 + 35.5

= 36.5 g/mol

Mass of HCl = 0.22 g

Mole of HCl =?

Mole of HCl = 0.006 mole Next, we shall determine the volume of the solution.

Density of solution = 1.110 g/mL

Mass of solution = 1 g

Volume of solution =?

Cross multiply

1.110 × Volume = 1

Divide both side by 1.110

Volume = 0.9 mL

Divide by 1000 to express in litres (L)

Volume of solution = 0.0009 LFinally, we shall determine the molarity of the solution.

Mole of HCl = 0.006 mole

Volume of solution = 0.0009 L

Molarity =?

Molarity of solution = 6.67 M

Therefore, the molarity of the solution is 6.67 M.

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  remember that hf is only the energy of one photon. not two. not three. one.  1) 5.12 * 10^3 photons  find the energy of one photon, then determine how many photons are needed to reach the sensitivity.  e = hf  = (6.626 * 10^-34 js)(5.95 * 10^19 hz)  = 3.94247 * 10^-14 j per photon  (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons  round to three sig figs.  2) 5.77 * 10^-17 j  energy of pulse = energy per photon * number of photons  = hfn  = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250)  = 5.774559 * 10^-17 j  round to three sig figs.  3) 4.07 * 10^8 kj/mol  10^12 pm = 1 m  c = fλ  f = c/λ  e = hf  = hc/λ  = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol)  = 40702571.4 kj/mol  round to three sig figs.  4) 9.94 * 10^-1 m  e = hc/λ  λ = hc / e  = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j)  = 0.9939 m  round to three sig figs.  5) 9.06 * 10^3 photons  energy of pulse = energy per photon * number of photons  number of photons = energy of pulse / energy per photon  = energy of pulse / (hf)  = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)]  = 9055.23695 photons  round to three sig figs.  6) 2.78 * 10^-15 j  this is problem 1, except in reverse.  sensitivity = minumum number of photons * energy per photon  = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz)  = 2.78070758 × 10^-15 j  round to three sig figs.