Suppose you wanted to make the smaller glass "disappear," that is, make it appear to be invisible. How would the index of refraction of the liquid inside have to compare to the index of refraction of the glass? Explain your reasoning.

maybe the spark is gone, love is a weird emotion and there is a possibility he may have found somebody else.

it's filtration, but this is an assumption so my apologies if i got this

gas

explanation:

smoke is the matter of a gas

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.