The balanced chemical equation for the reaction between sodium chloride and silver nitrate is: NaCl(aq) AgNO3(aq) AgCl(s) NaNO3(aq) We can interpret this to mean: ... 1 mole of sodium chloride and moles of silver nitrate React to produce ... moles of silver chloride and moles of sodium nitrate

1 mole of NaCl reacts with 1 mole of AgNO₃ to produce 1 mole of AgCl and 1 mole of NaNO₃

Explanation:

The given reaction is a double decomposition (metathesis) reaction. A reaction in which the products are formed by the exchange of the ions present in the two reactants. NaCL and AgNO₃ exchange ions to form AgCl, which precipitates and NaNO₃.

The balanced equation for reaction is given below;

NaCl(aq) + AgNO₃(aq) > AgCl(s) + NaNO₃(aq)

In the reaction above, the mole ratio of the reactants to products is 1 : 1 ---> 1 : 1

This means that 1 mole of NaCl reacts with 1 mole of AgNO₃ to produce 1 mole of AgCl and 1 mole of NaNO₃.

Given the molar mass of the compounds above;

NaCl = 58.5 g/mol; AgNO₃ = 170 g/mol; AgCl = 143.5 g/mol; NaNO₃ = 85 g/mol

Therefore, 58.5 g of NaCl reacts with 170 g of AgNO₃ to produce 143.5 g of AgCl and 85 g of NaNO₃

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

explanation: