Chemistry, 14.07.2020 23:01, terrysizemore666

Consider the chemical equations shown here. P4(s) + 302(g) - P406(S) AH1 = -1,640.1 kJ
P4010(s) - P4(s) + 5O2(g) AH2 = 2,940.1 kJ
What is the overall enthalpy of reaction for the equation shown below?
Round the answer to the nearest whole number.
P406(S) + 2O2(g) → P4010(s)
DONE

Answers: 1

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answered: bananaslada

-1,300 kJ

Explanation:

P₄ + 3 O₂ ⇒ P₄O₆ ΔH = -1,640.1 kJ (EQ 1)

P₄O₁₀ ⇒ P₄ + 5 O₂ ΔH = 2,940.1 kJ (EQ 2)

These are the equations you are given. You need to make these equations into the equation below.

P₄O₆ + 2 O₂ ⇒ P₄O₁₀ (end equation)

Look at the product side of the end equation. You need to produce P₄O₁₀. In the EQ 2, P₄O₁₀ is on the reactant side. Flip the equation. Since you flipped the equation, the enthalpy will have the opposite sign.

P₄ + 5 O₂ ⇒ P₄O₁₀ ΔH = -2,940.1 kJ

On the reactant side of the end equation, you need P₄O₆ and 2 O₂. First, rearrange the equation so that P₄O₆ is on the right side. In EQ 1, P₄O₆ is on the product side. Flip the equation. Like the last one, the sign will change.

Now, cancel out all possible values. P₄ will cancel out since there is one on each side of the equation. Since there is 5 O₂ on one side and 3 O₂ on the other, subtract the two and put the remainder on the side of the larger value.

P₄ + 5 O₂ ⇒ P₄O₁₀ ΔH = -2,940.1 kJ

P₄O₆ ⇒ P₄ + 3 O₂ ΔH = 1,640.1 kJ

P₄O₆ + 2 O₂ ⇒ P₄O₁₀

This should be the resulting equation. Now, add the two enthalpies together to find the overall enthalpy.

-2,940.1 kJ + 1,640.1 kJ = -1,300 kJ

The overall enthalpy is -1,300 kJ.

answered: Guest

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answered: Guest

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Consider the chemical equations shown here. P4(s) + 302(g) - P406(S) AH1 = -1,640.1 kJ
P4010(...