Mass box A = 10 grams; Mass box B = 5 grams; Mass box C-made of one A and one B How many boxes of B would be required to make 30 grams of C?
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2 boxes

Explanation:

==>Given that:

Box A = 10 grams

Box B = 5 grams

Box C= 1 A and 1 B = 15 grams

==>Required:

Number of boxes of B that would make 30 grams of C

==>Solution:

We know that, 1 box of B would give us 15grams of of C when mixed in the right proportion with 1 box of A.

thus,

1 box of B => 15 grams of C

x box of B => 30 grams of C

Therefore x = (30*1)/15

x = 30/15

x = 2

2 boxes of B would be required to make 30 grams of C

i just learnt this recently but i need to look through my notes again

the answers would be

the first one and the second one