The pressure of a 1-L nitrogen gas sample at 25 ⁰C is 0.30 atm. The pressure of a 1-L oxygen gas sample at the same temperature is 0.25 atm. The oxygen gas sample is added to the nitrogen container. Argon gas is added to the mixture until the total pressure of the 1-L container reaches 1.00 atm, and the temperature is adjusted to 25 ⁰C. According to Dalton’s Law of Partial Pressures, the contribution of each gas to the total pressure of the gas mixture is: Nitrogen Oxygen Argon

Nitrogen = 0.3 atm

Oxygen = 0.25 atm

Argon  = 0.45 atm

Explanation:

According to Dalton's law of partial pressure, the total pressure in the container is equal to sum of the partial pressures of the individual gases.

Given;

Total pressure of the gases, P_total = 1 atm

Pressure of nitrogen, P_nitrogen = 0.3 atm

Pressure of oxygen, P_oxygen = 0.25 atm

Pressure of argon, P_argon = ?

Therefore, the contribution of each gas to the total pressure of the gas mixture is;

Nitrogen = 0.3 atm

Oxygen = 0.25 atm

Argon  = 0.45 atm

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2