Chemistry, 15.07.2020 01:01, 29delphina
What is the pH of a 0.300 M NH₃ solution that has Kb = 1.8 × 10⁻⁵ ? The equation for the dissociation of NH₃ is: NH₃ (aq) + H₂O (l) ⇄ NH₄⁺ (aq) + OH⁻ (aq)
Answers: 1
![[OH^{-} ]=\sqrt{Kb \times Cb } = \sqrt{1.8 \times 10^{-5} \times 0.300 } = 2.3 \times 10^{-3} M](/tpl/images/0706/3859/9462d.png)
![pOH =-log[OH^{-} ]= -log(2.3 \times 10^{-3} M) = 2.6](/tpl/images/0706/3859/e37b1.png)
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What is the pH of a 0.300 M NH₃ solution that has Kb = 1.8 × 10⁻⁵ ? The equation for the dissociatio...
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