10 Points Determine the enthalpy change
of the following reaction: CH4 +
4Cl2 -> CCl4 + 4HCI
Given enthalpies:
CH4: -17.9 kJ/mol
Cl2: 0 kJ/mol
CCl4: -95.98 kJ/mol
HCI: -92.3 kJ/mol
A. -170.38
B.-206.18
C.-447.28 kJ/mol
OD.-393.58
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