For the given reaction, what volume of CO2 can be produced from 0.90 L of O2 , assuming an excess of CO ? Assume the temperature and pressure remain constant. g

1.8L of CO2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2CO + O2 —> 2CO2

Next we shall determine the volume of O2 that reacted and the volume of CO2 produced from the balanced equation. This is illustrated below:

1 mole of O2 reacted

Recall: 1 mole of any gas occupy 22.4L at stp

Therefore 1 mole of O2 = 22.4L

2 moles of CO2 were produced

2 moles of CO2 = 2 x 22.4 = 44.8L

Summary:

From the balanced equation above,

22.4L of O2 reacted to produce 44.8L of CO2.

Finally, we shall determine the volume of CO2 produced from 0.90L of O2. This can be obtained as follow:

From the balanced equation above,

22.4L of O2 reacted to produce 44.8L of CO2.

Therefore, 0.90L of O2 will react to produce = (0.9 x 44.8)/22.4 = 1.8L of CO2.

Therefore, 1.8L of CO2 were produced.

assuming that your periodic table has eighteen columns, you should highlight   the four elements in the third column from the left of the table.

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the have energy higher than those in the orbital while lower than those of the orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the orbital is therefore filled right after orbitals and before orbitals.  

potassium has electron configuration and calcium . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the and should be highlighted as well.