What is the chemical equation for the burning of propane if all the products and reactants are in the gas phase?

C3H8(g) + 5O2(g) —> 3CO2(g) + 4H2O(g)

Explanation:

The burning of propane is simply called Combustion of propane.

When an organic compound under goes Combustion, carbon dioxide, CO2 and water, H2O are produced respectively.

Thus, the burning of propane will yield the following:

C3H8(g) + O2(g) —> CO2(g) + H2O(g)

Now, let us balance the equation. This is illustrated below:

C3H8(g) + O2(g) —> CO2(g) + H2O(g)

There are 3 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 3 in front of CO2 as shown below:

C3H8(g) + O2(g) —> 3CO2(g) + H2O(g)

There are 8 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of H2O as shown below:

C3H8(g) + O2(g) —> 3CO2(g) + 4H2O(g)

There are 2 atoms of O on the left side and a total of 10 atoms on the right side. It can be balance by putting 5 in front of O2 as shown below:

C3H8(g) + 5O2(g) —> 3CO2(g) + 4H2O(g)

Now, the equation is balanced.