What is the concentration (M) of CH3OH in a solution prepared by dissolving 11.7 g of CH3OH in sufficient water to give exactly 100. mL of solution

Explanation:

We have to remember the molarity equation:

So, we have to calculate "mol" and "L". The total volume is 100 mL. So, we can do the conversion:

Now we can calculate the moles. For this we have to calculate the molar mass:

O: 16 g/mol

H: 1 g/mol

C: 12 g/mol

With the molar mass value we can calculate the number of moles:

Finally, we can calculate the molarity:

I hope it helps!

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