What would be the mass of Iron(II) chloride obtained when 450g of Sodium Chloride is added to Iron(II) oxide?

FeO(s)+2NaCL(aq)>FeCL2(aq)+Na2O(s)

2 moles of sodium chloride react with 1 mole of iron (II) oxide to give 1 mole of iron (II) chlorine

mole ratio NaCl :FeCl=2:1

mass of FeCl=0.5×450=225g

Explanation:

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