When 2,2-dimethylbutane is subjected to free-radical chlorination, distinct monochlorinated products are possible and of these contain asymmetric carbon atoms.

See the explanation

Explanation:

In this case, we have to remember that in the monochlorination products we only have to add one "Cl" with this in mind, we can have several options.

a) 1-chloro-2,2-dimethylbutane

b) (R)-3-chloro-2,2-dimethylbutane

c) (S)-3-chloro-2,2-dimethylbutane

d) 1-chloro-3,3-dimethylbutane

Additionally, from these 4 molecules, we will have 2 enantiomers. (R)-3-chloro-2,2-dimethylbutane and (S)-3-chloro-2,2-dimethylbutane.

See figure 1

I hope it helps!

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

give me abc and i will get it for u.