Above 882oC, zirconium has a BCC crystal structure with a = 0.332 nm. Below this temperature, zirconium has an HCP structure with a = 0.2978 nm and c = 0.4735 nm. Determine the percent volume change when BCC zirconium transforms to HCP zirconium. Is that contraction or expansion?

Contraction

Explanation:

From the given information;

Above 88° C

zirconium has a BCC crystal structure with a = 0.332 nm

Below this temperature

zirconium has an HCP structure with a = 0.2978 nm and c = 0.4735 nm

the volume of BCC can now be:

the volume of HCP can now be:

Ths; the volume percent change when BCC zirconium transforms to HCP zirconium can be calculated as:

Hence; it is contraction due to what the negative sign portray, The negative sign signifies that there is contraction during cooling

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation:

we need the questions , i may then you.