Determine the quantity (g) of pure MgSO4 in 2.4 g of MgSO4•7H2O. Show your work.

The quantity of pure in 2.4 g of is 1.17 g

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number of particles.

To calculate the moles, we use the equation:

As 1 mole of contains = 1 mole of

Thus 0.0098 moles of contains = of

Mass of

Thus the quantity of pure in 2.4 g of is 1.17 g

? you expect us to answer this? ? this is your schoolwork, i don't think we can with this, i think it would considering being

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.