To double the average kinetic energy of helium atoms in a balloon at 27 °C, the temperature of the gas must be

54°C

Explanation:

Hello,

To find the temperature of the gas, we would need a relationship between kinetic energy and temperature.

K.E = 3/2RT/Na

Where K.E = kinetic energy

R = ideal gas constant

T = temperature of the ideal gas

Na = Avogadro's number

2K.E₁ = K.E₂ (required)

Since both constant (R and Na) are equal,

K.E = T (direct proportionality)

But T = 27°C

T2 = 2 × 27 = 54°C

To double the kinetic energy of a helium gas at 27°C the temperature of the gas should be increased to 54°C

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.

that tool would be a compass