"Strike anywhere matches contain the compound tetraphosphorus trisulfide, which burns to form tetraphosphorus decaoxide and sulfur dioxide gas. How many milliliters of sulfur dioxide, measured at 751 torr and 21.0°C, can be produced from burning 0.869 g of tetraphosphorus trisulfide?"

Can be produced 288mL of SO₂

Explanation:

Based in the reaction:

P₄S₃ + 8O₂ → P₄O₁₀ + 3SO₂

Where 1 mole of tetraphosphorus trisulfide reacts producing 3 moles of sulfur dioxide gas.

0.869g of tetraphosphorus trisulfide (Molar mass of P₄S₃: 220.09g/mol) are:

0.869g P₄S₃ ₓ (1mol / 220.09g) = 3.948x10⁻³ moles of P₄S₃

As 3 moles of SO₂ are produced per mole of P₄S₃:

3.948x10⁻³ moles of P₄S₃ ₓ (3 moles SO₂ / 1 mole P₄S₃) = 0.0118 moles SO₂

Using PV = nRT

V = nRT / P

Where n are 0.0118 moles, R gas constant (0.082atmL/molK), T absolute temperature (21.0°C + 273.15K = 294.15K), and P pressure (751torr / 760 = 0.988atm).

Replacing:

V = 0.0118molₓ0.082atmL/molKₓ294.15K / 0.988atm

V = 0.288L = 288mL

i think the answer is terrae but not 100 percent sure. ▓▬▬ §

here is table 2-2:

country

percent of eligible voters that voted

rank

united states

44.9%

138

canada

60.1%

107

costa rica

84.6%

14

hungary

66.9%

82

japan

57.0%

118

egypt

27.7%

159

south africa

85.5%

10

ans is no, the data set cannot be plotted as a single circle graph