How many aluminum ions are there in 1.46 mol Al2S3? Express your answer to three significant figures.

There are alumnium ions in 1.46 mol

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles.

1 mole of contains = 2 moles of ions

Thus 1.46 mole of contains = moles of ions

Now 1 mole of contains = ions

Thus 2.92 moles of contains = ions.

There are alumnium ions in 1.46 mol

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.