If you have 1.82 x 1024 atoms of Oxygen in Oxygen Gas (O2), how many grams do you

have?

97g

Explanation:

Using the Avogadro's number; the following deductions can be made;

6.02 x 10 ∧23 atoms of oxygen has 32g.

1.82 x 10∧ 24 atoms of oxygen gas would have;

32 / 6.02 x 10 ∧23  x 1.82 x 10∧ 24 =  96.75g approximately 97g.

the electronic configuration of an atom with eight electrons is 1s²2s²2p⁴. the orbital diagrams are shown in the figure.

as per the hunds rule:

1. electrons tend to avoid being in the same orbital as per as practicable.

2. electrons in different orbitals of the same energy will have their spin parallel.

this can be illustrated from the multiplicity of the orbitals of the atom. as there are four electrons in the p orbital and p orbital has 3 sub-shells. the electrons can be fed in different ways as shown in the figure but the correct orbital diagram will be as per the hunds rule.

c. heat could easily travel through the molecules in the air and escape/enter the flask. removing the air slows down the heat transfer.