One of the first steps in the enrichment of uranium for use in nuclear power plants involves a displacement reaction between UO2 and aqueous HF: UO2(s) + HF(aq) → UF4(s) + H2O(l) [unbalanced] How many liters of 2.27 M HF will react with 3.70 kg of UO2?

24.1 L of 2.27 M HF will react with 3.70 kg of

Explanation:

The balanced chemical reaction :

To calculate the number of moles, we use the equation:

According to stoichiometry :

1 mole of require = 4 moles of

Thus 13.7 moles of will require=  of

To calculate the volume for given molarity, we use the equation:

    .....(1)

Molarity of solution = 2.27 M

Volume of solution in L= ?

Putting values in equation 1, we get:

Thus 24.1 L of 2.27 M HF will react with 3.70 kg of

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