Answer the following question in the essay box below. Effect of Solvent: Record the results. H2O = alcohol = glycerin = In which liquid is the salt most soluble? Using the concept of `'Like dissolves like," explain why you got the results you did. Explain how the choice of solvent affects the dissolving process. Effect of Pulverizing: Record of dissolving times. crystal = pulverized = Why are the dissolving rates different? Effect of Temperature: Record of dissolving times. cold = hot Using the concepts of kinetic energy, describe why you found the results you did. Effect of Stirring: Record the times necessary to dissolve each sample. Record of dissolving time. stirred = unstirred = Perform the experiment again using hot tap water this time. Are there any differences in the results between the cold water experiment and the hot water experiment? Explain. Conclusions: Review the four factors of dissolving you have just investigated. Given the correct solvent for a solute, what could you do to hasten the solution process? 1. 2. 3.

If a hydrogen atom is neutral, it must also have  one electron. an oxygen atom (o) has an atomic number of eight (8). this means a neutral oxygen atom has eight protons and eight electrons. the element actium (ac) has an atomic number of 89, so it has 89 protons and 89 electrons in a neutral atom

It could possibly be beneficial if the experiment is successful.

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.