What mass of Iodine, (molar mass=253. 80 g/mol), must be used to prepare a .960m solution if 100.0g of ethanol, CH3CH2OH, is used?

24.37 g of iodine

Explanation:

We have to remember the molality equation:

In this case, the solvent is ethanol and the solute is iodine. So, we can start with the solvent, we have to convert from g to Kg:

We have the molality value, so we can solve for the number of moles:

Now, with the molar mass value we can find the grams of iodine:

We need 24.37 g of iodine.

I hope it helps!

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