Nitrogen forms more oxides than any other element. The percents by mass of in three different nitrogen oxides are (1) (II) and (III) 25.94 For each compound, determine (a) the simplest whole-number ratio of to and (b) the number of grams of oxygen per 1.00 of nitrogen.

Complete question;

Nitrogen forms more oxides than any other element. The percents by mass of N in three different nitrogen oxides are (|) 46.69%;(II) 36.85 %; (III) 25.94%. For each compound, determine (a) the simplest whole-number ratio of N to O, and (b) the number of grams of oxygen per 1.00 g of nitrogen.

a. (i) The ratio is 1:1 , the formula = NO  (ii)The ratio is 1 : 1.5 which is  2 : 3, the formula = N₂O₃  (iii) The ratio is 1 : 2.5 which is 2:5 , the formula = N₂O₅

b. (i)number of grams of oxygen = 53.31/46.69 = 1.14 g

(ii)number of grams of oxygen = 63.15/36.8 = 1.71 g

(iii)number of grams of oxygen = 74.06/25.94 = 2.855 g

Explanation:

a.

(i) The percentage by mass of the nitrogen in Nitrogen oxide (i) is 46.69% which is taken as 46.69 grams . Since the other element is oxygen the mass of oxygen will be 100 - 46.69 = 53.31 grams.

The relative atomic mass of Nitrogen and oxygen is 14 amu and 16 amu respectively.

Therefore, to know the whole number ratio of N and O we find the number of moles.

number of moles of N = 46.69/14 = 3.335

number of moles of O = 53.31/16 = 3.332

The ratio is 1:1 , the formula = NO

(ii)

number of moles of N = 36.85/14 = 2.632

number of moles of O = 63.15/16 = 3.947

The ratio is 1 : 1.5 which is  2 : 3, the formula = N₂O₃

(iii)

number of moles of N = 25.94/14 = 1.85

number of moles of O = 74.06/16 = 4.63

The ratio is 1 : 2.5 which is 2:5 , the formula = N₂O₅

b.

(i) 46.69 g of nitrogen  = 53.31 g of oxygen

1 g of nitrogen = ? of Oxygen

number of grams of oxygen = 53.31/46.69 = 1.14 g

(ii)

Using similar method in b(i)

number of grams of oxygen = 63.15/36.8 = 1.71 g

(iii)

Using similar method in b(i)

number of grams of oxygen = 74.06/25.94 = 2.855 g