Chemistry, 25.06.2020 02:01, brookcoyanpeus5y
The acetate ion is the conjugate base of the weak acid acetic acid. The value of Kb for CH3COO-, is 5.56×10-10. Write the equation for the reaction that goes with this equilibrium constant.
Answers: 3
![5.56\times 10^{-10}=\frac{[CH_3COOH]}{[CH_3COO^-]\times [H^+]}](/tpl/images/0693/5990/d4718.png)
donates a proton and thus behaves as an acid and forms 
which is called as the conjugate base of 
and the dissociation constant of bases is given by the term 
and is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios.![K_a=\frac{[CH_3COO^-]\times [H^+]}{[CH_3COOH]}](/tpl/images/0693/5990/0c492.png)
![K_b=\frac{[CH_3COOH]}{[CH_3COO^-]\times [H^+]}](/tpl/images/0693/5990/71be5.png)
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The acetate ion is the conjugate base of the weak acid acetic acid. The value of Kb for CH3COO-, is...
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