3. If you dissolve lead(II) nitrate and potassium iodide in water they will react to form lead(II) iodide and potassium nitrate. This is a double replacement reaction

A. Calculate the grams of lead(II) iodide that can be produced from 2,75 moles of
potassium iodide.

B. Calculate the grams of lead(II) iodide that are produced if.656 g of KNO; are
produced
Pb(NO3)2(aq) + KI (aq) → Pbl (s) + KNO, (aq)

yes

explanation:

search chemistry final b exam in google and a site called quizlet will pop up

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"