A 2.04 g lead weight, initially at 10.8 oC, is submerged in 7.62 g of water at 52.3 oC in an insulated container. clear = 0.128 J/g oF; water = 4.18 J/goC. What is the final temperature of both the weight and the water at thermal equilibrium

The final temperature of both the weight and the water at thermal equilibrium is .

Explanation:

The given data is as follows.

mass = 7.62 g,          

Let us assume that T be the final temperature. Therefore, heat lost by water is calculated as follows.

       q =    

          =

Now, heat gained by lead will be calculated as follows.

       q =  

           =

According to the given situation,

     Heat lost = Heat gained

=

        T =

Thus, we can conclude that the final temperature of both the weight and the water at thermal equilibrium is .

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conduction is the transfer of thermal energy (heat in transfer) due to collisions between the molecules in the object. collisions between adjacent atoms and molecules transfer kinetic energy from the warmer to the cooler object. the objects must be in physical contact.