How many atoms are present in 3.42E23 molecules of Cu Cl?

3.42 × 10²³ atoms CuCl

General Formulas and Concepts:

Explanation:

Step 1: Define

3.42E23 molecules CuCl

3.42 × 10²³ molecules CuCl

Step 2: Convert (DA)

= 3.42 × 10²³ atoms CuCl

Step 3: Check

We have 3 sig figs. Follow sig fig rules.

Since our answer already has the correct number of sig figs, there is no need to change it.

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole