SO2Cl2(g)⇌SO2(g)+Cl2(g) Kc=2.99×10−7 at 227 ∘C You may want to reference (Page) Section 15.8 while completing this problem. Part A If a reaction mixture initially contains 0.186 MSO2Cl2, what is the equilibrium concentration of Cl2 at 227 ∘C?

2.36×10^–4 M

Explanation:

The following data were obtained from the question:

Equilibrium constant, Kc = 2.99×10^−7

Concentration of SO2Cl2, [SO2Cl2] = 0.186 M

Concentration of Cl2, [Cl2] =?

Next, we shall write the balanced equation for the reaction. This is given below:

SO2Cl2(g)⇌SO2(g)+Cl2(g)

Next, we shall we shall construct the initial concentration and equilibrium table (ICE). This is illustrated below:

Initial concentration:

[SO2Cl2] = 0.186 M

[SO2] = 0

[Cl2] = 0

During reaction:

[SO2Cl2] = –y

[SO2] = +y

[Cl2] = +y

Equilibrium:

[SO2Cl2] = 0.186 – y

[SO2] = y

[Cl2] = y

Next, we shall determine the value of y in order to obtain the concentration of Cl2. This can be achieved by doing the following:

Kc = [SO2] [Cl2] / [SO2Cl2]

Kc = 2.99×10^−7

[SO2Cl2] = 0.186 M

[SO2] = y

[Cl2] = y

2.99×10^−7 = (y × y) /0.186

Cross multiply

y × y = 2.99×10^−7 × 0.186

y² = 2.99×10^−7 × 0.186

Take the square root of both side:

y = √(2.99×10^−7 × 0.186)

y = 2.36×10^–4

Therefore, the concentration of Cl2, [Cl2] = y = 2.36×10^–4 M

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.