Calculate [NO3-] if 125 mL of 0.35 M NaNO3 is mixed with 450 mL of 1.1 M Mg(NO3)2. Please include some of your work as best as you can in the answer for full marks.

1.76 M

Explanation:

To calculate the number of moles for given molarity, we use the equation:

    .....(1)

Molarity of solution = 0.35 M

Volume of solution = 125 mL

Putting values in equation 1, we get:

a)

1 mole of contains = 1 mol of

Thus of contain= mol of

b)

1 mole of contains = 2 mol of

Thus of contain= mol of

Total

Thus after mixing is 1.76 M

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