What volume would 32.0g of NO¹² gas occupy at 3.12 ATM and 18.0°c? What volume would 32.0 g of nitrogen oxide gas occupy at 3.12 ATM and 18.0? Show working out

THE VOLUME OF 32 g OF NO GAS AT 3.12 atm AND 18 °C IS 79.30 L

Explanation:

Mass = 32 g

Pressure = 3.12 atm

Temperature = 18 °C = 18 + 273 K=  291 K

Molar mass of gas NO = (14 + 16) = 30 g/mol

Gas constant = 0.82 L atm mol^-1 K^-1  

Volume = unknown

                    Using PV = nRT where: number of moles = mass / molar mass

PV = m RT / MM

V  = mRT / MM P

V = 32 *0.82 * 291 / 30 * 3.21

V = 7635.84 / 96.3

V = 79.30 L

The volume of 32 g NO gas at 3.21 atm and 18 °C is 79.30 L

c is the answer because when something is left after something evaporates that shows the chemical change.

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