A saturated solution of sulfur dioxide is prepared by dissolving SO2(g) in 100. g of water at 10.°C and standard pressure. Determine the mass of SO2 in this solution.
A.) 15g to 18g
B.) 40g to 43g
C.) 53g to 56g
D.) 6g to 8g

The correct option is;

A.) 15 g to 18 g

Explanation:

The solubility of sulfur dioxide at room temperature = 94 g/L of water forming sulfurous acid as follows;

SO₂ + H₂O ⇄ HSO₃⁻ + H⁺

Which is a partial reversibly association with water molecules

Whereby 1 liter of water weighs 1 kg

9.4 gram of SO₂ will dissolve in 100 g of water at room temperature of 23 to 24°C

The solubility increases as the temperature reduces therefore as shown from the sulfur dioxide solubility chart we have;

At 10°C the solubility of SO₂ (g) is midway between 150 g to 200 g per kg of water

Therefore;

The solubility of SO₂ (g) is between 15 g to 18 g per 100 of water.

we can conclude that the melting point of table salt is above room temperature (it's actually 801 deg c). the melting point of mercury must be below room temperature (- 39 deg c).

its first and third is your answer i did the qustion the fourth isnt right