How many moles of neon (Ne) gas have a volume of 2.2 L and a pressure of 0.83 atm at 283 K?
(The universal gas constant is 0.0821 L. atm/mol. K.)
O A. 13 mol
O B. 0.11 mol
O C. 42 mol
O D. 0.079 mol

D. 0.079 mol

Explanation:

This question involving the number of moles of neon (Ne) gas can be solved using the ideal gas law, also called the general gas equation.

The formula for the general gas equation is:

PV = nRT

Where;

P=pressure (atm)

V=volume (Litres)

n=amount of substance (mol)

R=ideal gas constant

T=temperature (K)

In this question, P is given as 0.83atm, V = 2.2L, R = 0.0821 L.atm/mol.K, T= 283K, n = ?

We calculate 'n' by making it the subject of the formula i.e.

PV= nRT

Divide both sides by RT, we have;

n = PV/RT

Hence, we input our values

n = 0.83 × 2.2 / 0.0821 × 283

n= 1.826 / 23.2343

n = 0.07859

Hence, n is approximately 0.079 mol

it's filtration, but this is an assumption so my apologies if i got this