Calculate the theoretical yield for the amount of sodium carbonate produced as a result of this chemical reaction. Record your final answer in the above data table. Calculate the percent yield using your theoretical yield and the amount of sodium carbonate that was actually recovered. Record your final answer in the above data table.

How did your calculated mass of sodium carbonate compare with the actual mass you obtained from the experiment? If the two masses are different, suggest reasons for the difference.

Predict the amount of water and carbon dioxide that was produced as a result of this reaction.

1.

Mass of crucible

5.26 g

2.

Mass of crucible & NaHCO3

8.27 g

3.

Mass of NaHCO3 (2-1)

3.01g

4.

Theoretical Yield of Na2CO3
(Use the amount calculated in #3 as your starting amount)

g

5.

Mass of crucible & Na2CO3

7.13 g

6.

Mass of Na2CO3 – Actual Yield (5-1)

1.87 g

7.

% Yield = actual yield x 100
theoretical yield

%

98.6%

Explanation:

First we put down the equation representing the decomposition of sodium bicarbonate.

2NaHCO3(s) > Na2CO3(s) + H2O(l) + CO2(g)

We can see from the data provided that the mass of sodium bicarbonate reacted is 3.01 g.

The number of moles of sodium bicarbonate reacted= mass of sodium bicarbonate/ molar mass of sodium bicarbonate

Molar mass of sodium bicarbonate= 84.007 g/mol

Number of moles of sodium bicarbonate=3.01 g/ 84.007 g/mol

Number of moles of sodium bicarbonate= 0.0358 moles

From the balanced reaction equation,

2 moles of sodium bicarbonate yields 1 mole of sodium carbonate

Hence 0.0358 moles of sodium bicarbonate yields 0.0358/2 = 0.0179 moles of sodium carbonate

Theoretical yield of sodium carbonate = number of moles of sodium carbonate × molar mass of sodium carbonate

Molar mass of sodium carbonate= 105.9888 g/mol

Theoretical yield of sodium carbonate= 0.0179 moles × 105.9888 g/mol

Theoretical yield of sodium carbonate= 1.897 g

Actual yield of sodium carbonate= 1.87 g

%yield of sodium carbonate= 1.87/1.897 ×100

%yield of sodium carbonate= 98.6%

i just calculated it all out, and not including weekends, and all the different days off. as of this school year (2018-2019) students are spending 2198 hours in school this year