A geochemist in the field takes a 46.0 mL sample of water from a rock pool lined with crystals of a certain mineral compound X. He notes the temperature of the pool, 21°C, and caps the sample carefully. Back in the lab, the geochemist filters the sample and then evaporates all the water under vacuum. Crystals of X are left behind. The researcher washes, dries and weighs the crystals. They weigh 0.87 g. Required:
Using only the information above, can you calculate the solubility of X in water at 21°C? If yes, calculate it.

The solubility of X in water is g/ml.

Explanation:

The given data is as follows.

Volume of sample water = 46 ml

Temperature =

After vaporization, washes and then drying the weight of mineral X = 0.87 g

This means that 46.0 ml of water contains 0.87 g of X. Therefore, grams present in 1 ml of water will be calculated as follows.

          1 ml of water =

                                = g/ml

Therefore, we can conclude that solubility of X in water is g/ml.

mention the spill to the teacher clean the area and throw the broken pieces away

explanation:

acid rain does not usually kill trees directly. instead, it is more likely to weaken the trees by damaging their leaves, limiting the nutrients available to them, or poisoning them with toxic substances slowly released from the soil. the main atmospheric pollutants that affect trees are nitrates and sulphates.