g 1. An ideal gas is confined to a container with adjustable volume. The number of moles, n, and temperature, T, are constant. By what factor will the volume change if pressure decreases by a factor of 8.5 Hint: pV

The volume will increase by a factor of 8.5

Explanation:

In an ideal gas, the volume is inversely proportional to the pressure. This means that the volume will decrease when the pressure increases and vice versa.

Let  the initial volume be v1, and the initial pressure p1.

the final pressure is decreased by a factor of 8.5, i.e

p2 = p1/8.5 = 0.12p1

using p1v1 = p2v2

v2 = (p1/p2)v1

v2 = (p1/0.12p1)v1

v2 = 8.5v1

This means that the final pressure increases by a factor of 8.5

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.