A galvanic (voltaic) cell consists of an electrode composed of magnesium in a 1.0 M magnesium ion solution and another electrode composed of silver in a 1.0 M silver ion solution, connected by a salt bridge. Calculate the standard potential for this cell at 25 °C.

3.17 V

Explanation:

The cell is operating under standard conditions. These standard conditions include; that the reaction takes place at 298 Kelvin (room temperature), the pressure of the system is 1 atmosphere (standard pressure), and the solutions have a Molarity of 1.0 M for both the anode and cathode solutions. All these conditions are satisfied in the cell under review in the question.

Hence;

E°anode (magnesium)= -2.37 V

E°cathode (silver) = 0.80 V

E°cell= E°cathode -E°anode

E°cell= 0.80-(-2.37)

E°cell= 0.80 + 2.37

E°cell= 3.17 V

Hence the standard cell potential of this cell at 25°C is 3.17 V

answer: c.

explanation:

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.