In a lab, 400 ML of hydrogen gas reacts with 400 ML of chlorine gas. what product would form and how much of the product would form? PLEASE ANSWER ASAP

The product is hydrogen chloride gas

Volume of product = 800 ml

Explanation:

Equation of the reaction;

H2 + Cl2 > 2HCl

From the above balanced chemical equation, 1 mole of hydrogen gas, H2 reacts with 1 mole of chlorine gas, Cl2 to produce 2 moles of hydrogen chloride gas, HCl.

The mole ratio of reactants and products is 1 : 1 ---> :2

According to Gay-Lussac's law of combining volume which states that the volume of gases which take part in a chemical reaction bear a simple whole number ratio to one another and to the volume of products, if gaseous, at constant temperature and pressure.

Therfore, if 400 ml each of hydrogen and chlorine gas react, the product will be 2 * 400 ml of Hydrogen chloride gas = 800ml of hydrogen chloride gas

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.