2KMnO4= K2MnO4+ MnO2+O2 how many grams of KMnO4 are required to produce 1.60 grams of O2

15.8 g of will be required to produce 1.60 grams of

Explanation:

To calculate the moles :

According to stoichiometry :

As 1 mole of is given by = 2 moles of

Thus 0.05 moles of is given by =  of

Mass of

Thus 15.8 g of will be required to produce 1.60 grams of

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.