How many liters of bromine are needed to produce 12 miles of aluminum bromide?

0.929L of Br2

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2Al + 3Br2 —> 2AlBr3

Next, we shall determine the number of mole of Br2 needed to produce 12 moles of AlBr3. This is illustrated below:

From the balanced equation above,

3 moles of Br2 reacted to produce 2 moles of AlBr3.

Therefore, Xmol of Br2 will produce 12 moles of AlBr3 i.e

Xmol of Br2 = (3 x 12)/2

Xmol of Br2 = 18 moles

Therefore, 18 moles of Br2 reacted to produce 12 moles of AlBr3.

Next, we shall convert 18 moles of Br2 to grams. This is illustrated below:

Number of mole Br2 = 18 moles

Molar mass of Br2 = 2 x 80 = 160g/mol

Mass of Br2 =.?

Mass = mole x molar mass

Mass of Br2 = 18 x 160 = 2880g

Next, we determine the volume of Br2 used in the reaction as follow:

Mass of Br2 = 2880g

Density of Br2 = 3.1g/mL

Volume of Br2 =..?

Density = Mass /volume

Volume = Mass /Density

Volume of Br2 = 2880/3.1

Volume of Br2 = 929mL

Finally, we shall convert 929mL to L.

1000mL = 1L

Therefore, 929mL = 929/1000 = 0.929L

Therefore, 0.929L of Br2 were used in the reaction.

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )