How many milliliters of .75 M hydrochloric acid (HCl) are required to neutralize 60.0 ml of .3 M potassium hydroxide (KOH)?

24 millilitres

Explanation:

The reaction between hydrochloric acid (HCl) and potassium hydroxide (KOH) is as following:

HCl + KOH => KCl + H2O

Here, Molarity of KOH = 0.3 M per liter

1L = 1000ml

60ml = 0.06 L

moles of KOH = 0.3 x 0.060  L = 0.018 mol (Normalize the volumes)

Molarity of HCL = 0.75 M per liter

Therefore, volume of HCl =   = 0.024 L

Hence, volume of HCl = 24 millilitres

dynamic equilibrium is the answer.

hurricanes form when warm, moist air from the ocean surface quickly rises into the atmosphere and forms storm clouds and rain. when the clouds are formed, heat is released which warms the cool air in the upper regions of the atmosphere so that the cycle can continue. which two phases of the water cycle are repeated in this process?