Question 4 A mixture of xenon and oxygen gas is compressed from a volume of to a volume of , while the pressure is held constant at . Calculate the work done on the gas mixture. Round your answer to significant digits, and be sure it has the correct sign (positive or negative).

atm L

Explanation:

Complete question

A mixture of krypton and oxygen gas is expanded from a volume of 23.0L to a volume of 81.0L, while the pressure is held constant at 21.0atm. Calculate the work done on the gas mixture. Be sure your answer has the correct sign (positive or negative) and the correct number of significant digits.

Solution

As we know that -

Work done is equal to the product of pressure applied and change in the difference of volume of two liquids.

This can be represented mathematically as follows -

Where W represents the work done

P represents the change in pressure

is the final volume  and

is the initial volume

Substituting the given values in above equation, we get -

atm L

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answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole