If 1.50 L of 0.780 mol/L sodium sulfide, Na2S, is mixed with 1.00 L of a 3.31
mol/L lead(II) n...
Chemistry, 31.05.2020 03:03, deedeesmoke113057
If 1.50 L of 0.780 mol/L sodium sulfide, Na2S, is mixed with 1.00 L of a 3.31
mol/L lead(II) nitrate, Pb(NO3)2,"solution, what mass of precipitate would
you expect to form? The molar mass of PbS is 239.28 g/mol.*
Answers: 2
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Answers: 3
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