Chemistry, 30.05.2020 17:59, chicacrazy8338
To determine [H3O+] in 0.00250 M HNO2(aq)(Ka=4.5.×10−4), the first equation we would obtain in solving for x=[H3O+] isKa=[H3O+][NO2−][HNO2]=x20.00250−x Normally when x<5% Minitial, we solve this equation using the quadratic formula. This tutorial will lead you through an alternative method called successive approximations.
Now you will solve the same problem as above, but using the quadratic formula instead of iterations, to show that the same value of x is obtained either way. Using the quadratic equation to calculate [H3O+] in 0.00250 M HNO2, what are the values of a, b, c and x , where a, b, and c are the coefficients in the quadratic equation ax2+bx+c=0, and x is [H3O+]? Recall that Ka=4.5×10−4 .
Answers: 3
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What is the nature of the ca-cl bond in a molecule of calcium chloride (cacl2) if the electronegativity value of calcium is 1.0 and that of chlorine is 3.16?
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Chemistry, 22.06.2019 06:00, kylieweeks052704
Which of the following did jj thompson discover about atoms? a)an atom has an internal structure. b) atoms are tiny indivisible particles. c)electrons orbit the nucleus of an atom. d) the nucleus of an atom contains protons and neutrons.
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To determine [H3O+] in 0.00250 M HNO2(aq)(Ka=4.5.×10−4), the first equation we would obtain in solvi...
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