Hydrochloric acid reacts with lead (II) oxide to make lead (II) chloride and water. How many grams of hydrochloric acid are needed to make 215 moles of lead (II) chloride?

___HCl +PbO> PbCl2+H2O

grams of HCl is required to produce  215 moles of lead (II) chloride

Explanation:

The balanced equation for this reaction is

2HCl + PbO -----> PbCl2 + H2O

2 molecule of HCl combines with one molecule of PbO to form one molecule of PbCl2 and one molecule of H2O

Molar mass of lead (ii chloride) - g/mol

Mass of moles of lead (II) chloride is

Mass of two molecules of HCl grams

gram of PbO2 is formed by grams of HCL

1 gram of PbO2 is formed by grams of HCL

gram of PbO2 is formed by grams of HCL

grams of HCl is required to produce  215 moles of lead (II) chloride

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation:

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890