In a system in which the enthalpy changed –447.1 kJ/mol and the entropy decreases by 75.1 kJ/mol•K, calculate the temperature at which the system will be at equilibrium.

5.95 K

Explanation:

The relationship between enthalpy (H), entropy (S)) and temperature (T) is given by;

ΔG = ΔH - TΔS

At equilibrium, ΔG = 0

ΔH = –447.1 kJ/mol

ΔS = - 75.1 kJ/mol•K (Negative because it decreased)

Substituting back ito the formulae, we have;

0 = –447.1 - T (- 75.1 )

447.1 = 75.1(T)

T = 447.1 / 75.1 = 5.95 K

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.