What would be the pH at the equivalence point of a 0.01M solution of strong acid titrated using 45mL of 0.02Mof a strong base? *

Explanation:

We will first derive the volume of base to reach the equivalence point.

As we know that

Substituting the given values we get

Concentration of slat formed

H+ ion concentration is equal to

Substituting the given values in above equation, we get -

3 hours because it is a decent distance.

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%